What the minimum value of the function g(x) = x^2 - 6x - 12?
1 answer:
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We are given polynomial function f(x)=
We are given two zeros -4 and 5.
Therefore, x=-4 and x=5 is given.
So, the two factors of the polynomial will be (x+4)(x-5).
Let us write some steps to factor the given polynomial.
Let us take above factor (x+4) first.
On factoring (x+4) we get factors
Grouping
Factoring out gcf from each group, we get
So, the final factored form of given polynomial will be
For first to factors (x+4) and (x-5) we have given roots: -4 and 5.
Let us find the root of third factor we got.
Subtracting both sides by 1.
x^2 = - 1.
On taking square root on both sides, we get a square root(-1)
+ i and -i.
Those are imaginary solutions.
Therefore, correct option is B) No, there are two imaginary solutions.
Answer:
Step-by-step explanation:
I think the missing equation in your question is: h(t) = -16 + 16t + 480
Here is my answer:
As we know that the vertex form of a parabola, y=a + k where(h,k) is the vertex
h(t) = -16 + 16t + 480
= -16 ( + 480
= -16 + 484
So the vertex is ( , 484)
a. It take for Joseph second to reach his maximum height
b. The highest point that Joseph reached is the vertex of the function, it is 484 ft
c. Joseph hit the water after how many seconds?
<=> h(t) = 0
<=> -16 + 16t + 480 = 0
<=> t = second = 6 sec
Hope it will find you well
Answer:
r=
r= -
Step-by-step explanation:
8=
Square root both sides of the equation.
r=
r= -