Answer:
ΔCFE is a right triangle
ΔBEC is an acute triangle
ΔBFG is an equilateral triangle
ΔGAF is an obtuse isosceles triangle
A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
Answer:
102336
Step-by-step explanation:
Im bored
Answer:
#7000, #14000 and #28000 respectively
Step-by-step explanation:
#49000 to be shared in 1:2:4
49000 ÷ (1 + 2 + 4) = 49000/7 = #7000
A will get (7000×1) = #7000
B will get (7000×2) = #14000
C will get (7000×4) = #28000
