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RUDIKE [14]
2 years ago
9

The width of Abby's swimming pool is 24 feet. What is equal to 24 feet?

Mathematics
1 answer:
iren [92.7K]2 years ago
3 0
24 feet hhghhhhhhhhhhhhhhh
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Please help- I am very confused-
shusha [124]

Answer:

5÷9

Step-by-step explanation:

5/9 is a fraction where the numerator is divided by the denominator

5 divide by 9

5÷9

4 0
3 years ago
Read 2 more answers
56 projects 5:9 ratio divide
Alex Ar [27]
The answer is 4:4 it takes 4 of each





4 0
2 years ago
I need help pls !!!!!!
swat32

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Trigonometry.

here, we use the Linear pair property of the adjacent angles.

We know that, all the adjacent angles in a linear pair add to get 180°

so we get as,

=> (n+6) +90°+(2n+3) =180°

=> (n+6) +(2n+3) =180-90

=> 3n+9 = 90

=> 3n= 90-9

=> 3n = 81

hence, n = 81/3

=> n = 27°

thus the value of n is 27° .

4 0
3 years ago
Determine the kinetic energy of 8000 Newton’s roller coaster car that is moving with a speed of 20.0 meters/seconds
ohaa [14]

Answer:

The kinetic energy of the roller coaster is 1600000 J.

Step-by-step explanation:

Given:

Mass of the roller coaster is 8000 Newton's and speed 20.0 meters/seconds.

Now, we need to find the kinetic energy E_{k} of the roller coaster.

So, Mass of roller coaster (m) = 8000 N.

Velocity of roller coaster (v) = 20.0 m/s.

Now, putting the formula of kinetic energy:

E_{k} = \frac{1}{2}\times m\times v^{2}

E_{k}=\frac{1}{2} \times 8000\times 20^{2}

E_{k}=\frac{1}{2} \times 8000\times 400

E_{k}=\frac{1}{2} \times 3200000

E_{k}=1600000

Therefore, the kinetic energy of the roller coaster is 1600000 J.

3 0
3 years ago
Can someone help me with this ????
fenix001 [56]

Answer:

A.

(\frac{3}{3+5})(2 - (-14))+ (-14)

Step-by-step explanation:

Given

Ratio = 3:5

Q = -14

S = 2

Required

Which solution uses (\frac{m}{m+n})(x_2 - x_1)+ x_1

From the given parameters;

m:n = 2:5

m = 2\ and\ n = 5

x_1 = -14\ and\ x_2 = 2

Substitute the above values in (\frac{m}{m+n})(x_2 - x_1)+ x_1

This gives:

(\frac{m}{m+n})(x_2 - x_1)+ x_1

(\frac{3}{3+5})(2 - (-14))+ (-14)

<em>From the list of given options, only option A uses the given form of the formula...</em>

6 0
3 years ago
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