Answer:
h(x) = 1
Step-by-step explanation:
h(x) = both of these equations, but really only -6. Plug in 1 to x in the equation and it will equal -6.
Hope this helps
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for

is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of

is always positive for

. That means at

there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function

is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
52.5
Step-by-step explanation:
Answer:
972
Step-by-step explanation:
Answer:
11. x = -16
12. k = 6
13. x = -19
14. x = -6
15. x = -20
16. Combining like terms isn't to be used on this type of problem. I'm sorry, can you guess on this one?
17. x = 19
18. n = -10
19. b = 11
20. n = 4
21. r = -6
22. n = -4
Again super sorry about question 16 :(