3 years ago

(x+4)^2 - (x-6)^2 - (x-1)*(x+1)

Mathematics

1 answer:

Murrr4er [49]3 years ago

3 0

Answer:

-9

Step-by-step explanation:

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Help pls!?!?!?!!! This is algebra 2

Tresset [83]

$\boxed{\sf a_n=\dfrac{(-1)^n}{5n}}$

a:-

$\\ \sf\longmapsto a_1=\dfrac{(-1)^1}{5(1)}$

$\\ \sf\longmapsto a_1=\dfrac{-1}{5}$

$\\ \sf\longmapsto a_1=-5$

b:-

$\\ \sf\longmapsto a_4=\dfrac{(-1)^4}{5(4)}$

$\\ \sf\longmapsto a_4=\dfrac{1}{20}$

c:-

$\\ \sf\longmapsto a_{30}=\dfrac{(-1)^{30}}{5(30)}$

$\\ \sf\longmapsto a_{30}=\dfrac{1}{150}$

d:-

$\\ \sf\longmapsto a_{19}=\dfrac{(-1)^{19}}{5(19)}$

$\\ \sf\longmapsto a_{19}=\dfrac{-1}{95}$

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3 years ago

The sum of two numbers is 156. The first number is six more

melomori [17]

6 + 4x = 156

4x = 150
X = 37.5

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3 years ago

Which of the following numbers is irrational?

zalisa [80]

Answer:

square root of 5 my dude

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3 years ago

132 is what percent of 880

Mashcka [7]

Answer:

Step-by-step explanation:

132 is what percent of 880? = 15.

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3 years ago

Find the zeros of the function: f(x) = x2 -7x + 12 Write your answer like this example: x=2,3 with no spaces.

KATRIN_1 [288]

Whenever a quadratic equation is in the form

$x^2-sx+p$

(i.e. the leading terms is 1), you can solve it by looking for two numbers that give $s$ when summed and $p$ when multiplied.

So, in your case,

$x^2-sx+p = x^2-7x+12 \iff s = 7,\quad p=12$

So, we're looking for two numbers $x_1,\ x_2$ such that:

$x_1+x_2 =7,\quad x_1x_2=12$

you can clearly check that these numbers are 3 and 4.

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3 years ago