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3 years ago

How many solutions does y=(2-7)^2

Mathematics

1 answer:

vladimir1956 [14]3 years ago

3 0

I believe the equation y=(2-7)^2 has 1 solution which is y=25

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Find y.<br> 30<br> 20 <br> Need help asap

Neporo4naja [7]

Answer:

y = 10

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = $\frac{1}{2}$ , then

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{y}{20}$ = $\frac{1}{2}$ ( cross- multiply )

2y = 20 ( divide both sides by 2 )

y = 10

7 0

2 years ago

kali has a 6 centimeter ladder and puts the base of the ladder 2 meters away from the tree how high into the tree will the lader

weqwewe [10]

I am going to assume ‘centimetre’ was a typo.

A^2 + B^2 = C^2

C^2 - A^2 = B^2

32 = B^2

Square root both sides

B = 5.7m high

The ladder will reach 5.7 meters high

5 0

3 years ago

The engine life for a certain brand of lawn mower is modeled by the function f(h) = 50 - 1 3 h where h represents hours used. Wh

Colt1911 [192]

Answer: C. Engine life decreases steady with time.

Step-by-step explanation:

4 0

3 years ago

Find the length of each arc. Use the exact answer

Cerrena [4.2K]

Answer:

Option D = 16π/3 ft

Step-by-step explanation:

Arc length formula is written Mathematically as:

Arc length = 2πr × θ /360

r = 4 ft

θ = Central angle in degrees = 240°

2 × π × 4 × 240/360

8π × 240/360

8π × 20/30

16π/3 ft

So, the arc length is 16π/3 ft

3 0

2 years ago

The value of a house decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer) in

Westkost [7]

Answer: The total percentage loss would be 67%.

Step-by-step explanation:

Since we have given that

Rate of decline each year = 20%

Number of years = 5

We need to find the total percentage loss in value of the house at the end of 5 years.

So, Total percentage loss would be

$1-(1-\dfrac{r}{100})^5\\\\=1-(1-\dfrac{20}{100})^5\\\\=1-(\dfrac{4}{5})^5\\\\=1-(0.8)^5\\\\=0.67\\\\\approx 67%$

Hence, the total percentage loss would be 67%.

8 0

2 years ago