Answer:
e. 2
Step-by-step explanation:
Answer:
Rs 100x² + 150x - 100
Step-by-step explanation:
Area of the parking space = Length * Width
Area of the space = (2x-1)(x+2)
Expand
Area of the space = 2x² + 4x - x - 2
Area of the space = (2x²+3x - 2) sq. m
Since 1sq.m = Rs 50'
(2x²+3x - 2) sq. m= z
z = 50 (2x²+3x - 2)
z = 100x² + 150x - 100
hence the cost of the parking spsce is Rs.100x² + 150x - 100
Answer:
Step-by-step explanation:
an=an-1+(-4)
a2 = a1 + (-4) = 50 - 4 = 46
a3 = a2 - 4 = 46 - 4 = 42
a4 = a3 - 4 = 42 - 4 = 38
a5 = a4 - 4 = 38 - 4 = 34
Answer:
a. 5%
b. 55%
c. 70%
Step-by-step explanation:
a. The probability of customer wanting both services (P(O&T)) is:
![P(O)+P(T)+P(O\&T) = 0.75\\P(O)+P(O\&T) =0.60\\P(T)+P(O\&T) = 0.20\\P(O)+P(T)+P(O\&T) -[P(O)+P(T)+2P(O\&T)]=0.75 -(0.60-0.20)\\P(O\&T)=0.05=5\%](https://tex.z-dn.net/?f=P%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20%3D%200.75%5C%5CP%28O%29%2BP%28O%5C%26T%29%20%3D0.60%5C%5CP%28T%29%2BP%28O%5C%26T%29%20%3D%200.20%5C%5CP%28O%29%2BP%28T%29%2BP%28O%5C%26T%29%20-%5BP%28O%29%2BP%28T%29%2B2P%28O%5C%26T%29%5D%3D0.75%20-%280.60-0.20%29%5C%5CP%28O%5C%26T%29%3D0.05%3D5%5C%25)
The probability is 5%
b. The probability that the customer will need an oil change, but not a tire rotation (P(O)) is :

The probability is 55%
c. The probability that the customer will want exactly one of these two services (P(O)+P(T)) is:

The probability is 70%