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3 years ago

What is biodiversity in chemistry?

1 answer:

4 0

Answer:Biodiversity is typically a measure of variation at the genetic, species, and ecosystem level. Terrestrial biodiversity is usually greater near the equator, which is the result of the warm climate and high primary productivity. Biodiversity is not distributed evenly on Earth, and is richest in the tropics.

Explanation:

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PLEASE HELP ITS THE LAST OF MY POINTS MAKE IT YOURS!!! HELP

Troyanec [42]

A because saturation mean dissolve

8 0

3 years ago

Read 2 more answers

If 6.49 mol of ethane (C2H6) undergo combustion according to the unbalanced equation

MArishka [77]

Answer:

22.715 moles of oxygen are used

Explanation:

Given data:

Number of moles of ethane = 6.49 mol

Number of moles of O₂ required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Now we will compare the moles of oxygen with ethane.

C₂H₆ : O₂

2 : 7

6.49 : 7/2×6.49 = 22.715 mol

Thus, 22.715 moles of oxygen are used.

3 0

3 years ago

Amount of valence electrons KMnO4

Fantom [35]

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8 0

3 years ago

Complete the following reaction: Li + S -->

valina [46]

Answer:

Li2S

Explanation:

Hope this helps.

7 0

3 years ago

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Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago