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RoseWind [281]
3 years ago
12

Ice melting is not a chemical change because __________.

Chemistry
1 answer:
professor190 [17]3 years ago
3 0

Answer:

I think the answer of the question is C?

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Question 2: Heat (5 points)
Ronch [10]

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

8 0
3 years ago
_______ is force divided by area.
Digiron [165]

Answer:

Pressure

Explanation:

Basically when you are pressing something you are applying force over an area thus Pressure is force divided by area.

7 0
3 years ago
Read 2 more answers
_P4 + ____O2 → __P2O3<br><br> How do I balance this equation?
Murljashka [212]

Explanation:

please mark me as brainlest

5 0
3 years ago
Read 2 more answers
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128
alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

Explanation:

The given data is as follows.

mass = 7.62 g,           T_{2} = 10.8^{o}C

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q = mC \times \Delta T    

          = 7.62 g \times 4.184 J/^{o}C \times (52.3 - T)

Now, heat gained by lead will be calculated as follows.

       q = mC \times \text{Temperature change of lead}  

           = 2.04 \times 0.128 \times (T - 11.0)

According to the given situation,

     Heat lost = Heat gained

7.62 g \times 4.184 J/^{o}C \times (52.3 - T) = 2.04 \times 0.128 \times (T - 11.0)

        T = 50.26^{o}C

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is 50.26^{o}C.

7 0
3 years ago
Carry out some research into how new elements get their name and their symbols. Write out a short passage (no more than 50 words
spin [16.1K]
The IUPAC says that elements have to be named after one of five things: a scientist, a place, a mineral or substance, a descriptor of the element, or a mythological reference. Of the new elements, three are named after places and one is named after a person No-one has yet named an element after themselves but many elements are named in tribute to important scientists
(you can cut some stuff out)
6 0
3 years ago
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