Ask question

Ask question

All categories

4 years ago

10

What's the answer and how do u figure out number 5 only

1 answer:

shusha [124]4 years ago

6 0

The length of a segment knowing the coordinates of its end points:
(x₁,y₁) and (x₂,y₂) is given by the formula:

Length = √[(x₁ - x₂)² + (y₁ - y₂)²]

T(1,4) ; A(4,4) ; P(3,0)

a) TA =√[(1-4)²+(4-4)²] → TA = 3
b) AP =√[(4-3)²+(4-0)²] →AP = √17 = 1.123
c) TP =√[(1-3)²+(4-0)²] → TA = √20 = 4.472

Perimeter = TA + AP + TP = 8.60

You might be interested in

What expression is equivalent to 3(2t + 6) -4t

tekilochka [14]

Answer: 2t + 18

Step-by-step explanation:

3 0

3 years ago

URGENT!! ILL GIVE<br> BRAINLIEST! AND 100 POINTS

MatroZZZ [7]

Answer:

perimeter: add p + m + n

area: use (p × m)/2

find missing side: use p^2 + m^2 = n^2

3 0

1 year ago

There 400 members at the school band. Of those, 220 were girls. Expressed as a percentage, how many more girls than boys were th

GuDViN [60]

220/400 = 55%
100%- 55% = 45%
there were 45% more girls than there were boys.

3 0

3 years ago

The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.What is

Lesechka [4]

Answer:

a) The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

Step-by-step explanation:

Given : The gross weekly sales at a certain restaurant are a normal random variable with mean $2200 and standard deviation $230.

To find : What is the probability that

(a) the total gross sales over the next 2 weeks exceeds $5000;

(b) weekly sales exceed $2000 in at least 2 of the next 3 weeks? What independence assumptions have you made?

Solution :

Let $X_1$ and $X_2$ denote the sales during week 1 and 2 respectively.

a) Let $X=X_1+X_2$

Assuming that $X_1$ and $X_2$ follows same distribution with same mean and deviation.

$E(X)=E(X_1+X_2)=E(X_1)+E(X_2)$

$E(X)=2\mu = 2(220)=4400$

$\sigma_X=\sqrt{var(X_1+X_2)}$

$\sigma_X=\sqrt{2\sigma^2}$

$\sigma_X=\sqrt{2}\sigma$

$\sigma_X=230\sqrt{2}$

So, $X\sim N(4400,230\sqrt{2})$

$P(X>5000)=1-P(X\leq5000)$

$P(X>5000)=1-P(Z\leq\frac{5000-4400}{230\sqrt{2}})$

$P(X>5000)=1-P(Z\leq1.844)$

$P(X>5000)=1-0.967$

$P(X>5000)=0.0321$

The total gross sales over the next 2 weeks exceeds $5000 is 0.0321.

b) The probability that sales exceed teh 2000 and amount in at least 2 and 3 next week.

We use binomial distribution with n=3.

$P(X>2000)=1-P(X\leq2000)$

$P(X>2000)=1-P(Z\leq\frac{2000-2200}{230})$

$P(X>2000)=1-P(Z\leq-0.87)$

$P(X>2000)=1-0.1922$

$P(X>2000)=0.808$

Let Y be the number of weeks in which sales exceed 2000.

Now, $P(Y\geq 2)$

So, $P(Y\geq 2)=P(Y=2)+P(Y=3)$

$P(Y\geq 2)=^3C_2(0.8077)^2\cdot (1-0.8077)+^3C_3(0.8077)^3$

$P(Y\geq 2)=0.37635+0.52692$

$P(Y\geq 2)=0.90327$

The weekly sales exceed $2000 in at least 2 of the next 3 weeks is 0.9033.

3 0

3 years ago

Factorise using suitable identities<br> x^2 (y+z)^2

vredina [299]

Answer:

Step-by-step explanation:

$x^2 ( y +z)^2 = x^2 (y+z)(y+z)$ $[ \ (a+b)^2 = (a+b)(a+b) \ ]$

$x^2 - ( y +z)^2 = (x - ( y +z)) (x + (y+z))$ $[ \ a^2 - b^2 = (a-b)(a+b) \ ]$

$=(x-y-z)(x+y+z)$

8 0

4 years ago