Cancel something
we cancel x's
multiply 1st equation by 5 and 2nd by 7 and add them
-35x-30y=-5
<u>35x-28y=7 +</u>
0x-58y=2
-58y=2
divide both sides by -58
y=-1/29
sub back
5x-4(-1/29)=1
5x+4/29=1
minus 4/29 from both sides
note, 1=29/29
5x=25/29
divide bot sides by 5 (or times 1/5)
x=5/29
(5/29,-1/29)
An exponential function can be expressed as:
y=ab^x we have two points so we can solve
64/8=(ab^4)/(ab^1)
8=b^3
2=b, now we have:
y=a(2^x), using point (4,64)
64=a(2^4)
64=16a
4=a so
y=4(2^x)
Consider the equation:
Subtracting '4' from both the sides of the equation, we get as
Squaring on both the sides of the equation, we get
Subtracting '2' from both the sides of the equation, we get
x=14
Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.
Hence, it is not an extraneous solution.
Answer: −6+7
Step-by-step explanation: Trust
85
Also, this is 5 points.