Do these pairs of values (x and y) represent two quantities that are proportional?

AlexFokin [52]

Answer: Non linear

Step-by-step explanation:

x is increasing steadily at a constant rate however the change in the y values vary from x values and they are not constant so this line is non linear

6 0

3 years ago

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A right rectangular pyramid is sliced vertically (down) at the red line by a plane not passing through the vertex of the pyramid

crimeas [40]

The cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a rectangle. Hence, 4th option is the right choice.

If the peak of the rectangular pyramid is directly above the center of the base, it creates a perpendicular to the base, indicating the height of the pyramid. This type of rectangular pyramid is known as the right rectangular pyramid.

A rectangle is a quadrilateral, that is a closed figure with 4 line segments, with all four interior angles at 90°.

When we slice a right rectangular pyramid vertically down at the red line by a plane, not passing through the vertex, of the pyramid will be a dilated image of its base.

A dilated image is an enlarged or diminished image of the preimage, similar with all angles.

Thus, the cross-section of a right rectangular pyramid will be shaped similar to the base, that is, a rectangle. Hence, 4th option is the right choice.

Learn more about right triangular pyramids at

brainly.com/question/27658401

#SPJ4

For complete question, refer to the attachment.

5 0

2 years ago

Steve started with $250 and spent $25 per week. Chelsea started with $30 and saved $30 per week. Use x for time and y for saving

sergiy2304 [10]

Steve has 10000000000$
I look it up lol

8 0

3 years ago

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If g(x) = 8x^6 and f(x) = log4 (2x) then f(g(x)) = ?

Lena [83]

$\begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array} ~\hspace{4em} \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\begin{cases} g(x)=8x^6\\\\ f(x)=\log_4(2x) \end{cases}\qquad \qquad \begin{array}{llll} f(~~g(x)~~)=\log_4[~2g(x)~] \\\\\\ f(~~g(x)~~)=\log_4[~2(8x^6)~] \end{array} \\\\\\ f(~~g(x)~~)=\log_4(16x^6)\implies f(~~g(x)~~)=\log_4(4^2x^6) \\\\\\ f(~~g(x)~~)=\log_4(4^2)~~ + ~~\log_4(x^6)\implies \boxed{f(~~g(x)~~)=2~~ + ~~6\log_4(x)}$

8 0

3 years ago

Can you please tell me how to do easy way can you please show me in numbers how to multiply

almond37 [142]

same as before, we look at the denominators, hmmm do a quick prime factoring.

3 = 3 * 1

9 = 3 * 3 * 1

since 9 already contains 3 and 1, we can us that

$\cfrac{\underline{2}}{3}~~ - ~~\cfrac{1}{9}\implies \cfrac{(2)\underline{2}~~ - ~~(1)1}{\underset{\textit{using this LCD}}{9}}\implies \cfrac{4-1}{9}\implies \cfrac{\stackrel{1}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{3}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{1}{3}$

4 0

3 years ago