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Degger [83]
3 years ago
6

Avery invested $200 in an account paying an interest rate of 6 7/8%

Mathematics
2 answers:
Maslowich3 years ago
5 0

Answer:

0.73 yrs

Step-by-step explanation:

if t is time in years

quarterly

600 = 200(1 + 0.06625/4)^4t

3 = (1 + 0.06625/4)^4t

ln3 = 4tln(1. + 06625/4)

t = ln3 / (4ln1.0165625)

t = 16.7198 yrs

continuously

600 = 200e^(0.06875t)

3 = e^(0.06875t)

ln3 = 0.06875t

t = ln3 / 0.06875

t = 15.9798 years

Δt = 16.7198 - 15.9798 = 0.73 yrs

ElenaW [278]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
What is the degree of the following polynomial?<br> 15x + 9x2 - 6x3 + 1
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3

Step-by-step explanation:

the one have largest power

5 0
3 years ago
Read 2 more answers
Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:
ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = \frac{12}{36} =\frac{1}{3}

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = \frac{6}{36} =\frac{1}{6}

c) P(EF)

There is no common element between E and F

P(EF) =0

4 0
3 years ago
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There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is
malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

25,26,28,52,56,58,62,65,68,82,85,86

Hence, the required numbers.

2) Recall that probability is the ratio:

Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

P(A)=\frac{9}{12}=\frac{3}{4}

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

P(B)=\frac{3}{12}=\frac{1}{4}

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

P(C)=\frac{0}{12}=0

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

7 0
1 year ago
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