Answer:
9 seconds
Step-by-step explanation:
The complete question is
The altitude of an object, d, can be modeled using the equation below:
d=-16t^2 +vt+h
from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?
Let
d ----> the altitude of an object in feet
t ---> the time in seconds
v ---> initial velocity in ft per second
h ---> initial height of an object in feet
we have
we know that
When the arrow reach the water the value of d is equal to zero
we have
substitute the values and solve for t
Multiply by -1 both sides
The formula to solve a quadratic equation of the form 
is equal to
in this problem we have
substitute in the formula
the solution is t=9 sec
see the attached figure to better understand the problem
Answer:
Look below
Step-by-step explanation:
Part A: Equation would be in the y=mx+b format. m, or the slope, would be the cost that varies depending on the number of things that happen so m=3.25. b would be the fix cost so it is 15 so the equation ends up being y=$3.25x + $15.
Part B: Initial value is 15 since it is the fix cost, and 3.25 is the rate of change since it added as the number of rides increase.
Part 3: To solve this you substitute 7 into x so y=$3.25(7) + $15 = $37.75
I hope this explains it well.
Answer:
$76.80
Step-by-step explanation:
When a product has a certain markup, you need to multiply the markup by the price of the product, and then add that to the original price of the product. 20%=0.2, and 0.2*64=12.8. Adding this to the original price, you get 64+12.8=$76.80. Hope this helps!
Strategy A, drawing a diagram is the best strategy to solve this problem
Answer: 12 -8 = 4
Step-by-step explanation:
