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Bingel [31]
3 years ago
13

I don't know the answer to this question 5286-k=4319k=?​

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

k = -4033

Step-by-step explanation:

Solve for k:

286 - k = 4319

Subtract 286 from both sides:

(286 - 286) - k = 4319 - 286

286 - 286 = 0:

-k = 4319 - 286

4319 - 286 = 4033:

-k = 4033

Multiply both sides of -k = 4033 by -1:

(-k)/(-1) = -4033

(-1)/(-1) = 1:

Answer:  k = -4033

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What is the measure of x? (Geometry question involving circles...)
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Hope this Helped!

3 0
3 years ago
A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many diff
lys-0071 [83]

Answer:

The team can be formed in 756 different ways

Step-by-step explanation:

This is a combination problem since we are to select a set of people from a group. Combination has to do with selection.

for example, if r number of object is to be selected from a pool of n objects, this can be done in nCr number of ways.

nCr = \frac{n!}{(n-r)!r!}

Now If A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team, then this can be done in the following way;

7C2 * 9C2

7C2 = \frac{7!}{5!2!} \\= \frac{7*6*5!}{5!*2} \\= 7*3\\= 21ways\\\\similarly;\\\\9C2 = \frac{9!}{7!2!}\\9C2= \frac{9*8*7!}{7!*2} \\9C2 = 9*4\\9C2 = 36

7C2 * 9C2 = 21*36

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The team can be formed in 756 different ways

5 0
3 years ago
Solve for x. Leave your answer in simplest radical form.
strojnjashka [21]

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

\boxed{ \large \boxed{h {}^{2}  =  {b}^{2} + p{}^{2}  }}

note :

  • p = perpendicular / opposite side
  • b = base / adjacent side
  • h = hypotenuse

let's solve for " y² " first ( square of other missing side )

➢ \:  \:  {y}^{2}  =  {8}^{2}  + 3 {}^{2}

➢ \:  \:  {y}^{2}  = 64 + 9

➢ \:  \:  {y}^{2}  = 73

now let's solve for " x " , by using pythagorous theorem

➢ \:  \:  {x}^{2}  =  {y}^{2}  +  {6}^{2}

➢ \:  \:  {x}^{2}  = 73 + 36

➢ \:  \:x {}^{2}  =  109

➢ \:  \: x =  \sqrt{109}

Approximate :

➢ \:  \: 10.44 \:  \: units

\mathrm{✌TeeNForeveR✌}

5 0
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