How do I do this 20 points to whoever completes this.

(x+3)(3x² - 5x - 10) multiply polynomial

brilliants [131]

Answer:

$\boxed{\sf{3x^3+4x^2-25x-30}}$

Step-by-step explanation:

$\underline{\text{SOLUTION:}}$

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

$\underline{\text{GIVEN:}}$

$:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}$

You have to solve with parentheses first.

$:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}$

Solve.

$\sf{x*3x=3x^3}$

x(-5x)=-5x²

$\sf{x(-10)=-10x}$

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

Then, rewrite the problem down.

$\sf{3x^3-5x^2-10x+9x^2-15x-30}$

Combine like terms.

$\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}$

Add/subtract the numbers from left to right.

-5x²+9x²=4x²

$\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}$

Solve.

$\sf{-10x-15x=-25x}$

Then rewrite the problem.

$\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}$

Therefore, the correct answer is 3x³+4x²-25x-30.

I hope this helps! Let me know if you have any questions.

6 0

2 years ago

Read 2 more answers

A widget inspector inspects 12 widgets and finds that exactly 3 are defective.Unfortunately, the widgets then get all mixed up a

WITCHER [35]

Answer:

0.7455

Step-by-step explanation:

First, we note that there are C $C_{12|3}$ = 220 ways of selecting the defective items.

The probability that the inspector will have to test at least 9 widgets would be 1 minus the probability that the inspector will have to test 8 or less widgets.

This is 1 - P(8 or less widgets have to be checked)

1 - $\frac{C_{8|3} }{C_{12|3} }$

= 1 - 56/220

= 1 - 0.2545

= 0.7455

8 0

3 years ago

Read 2 more answers

I need an answer to this asap... please ....just number 3

Agata [3.3K]

Answer:

hence cos ( 2 A ) = cos 2 A − ( 1 − cos 2 A ) = 2 cos 2 A − 1

Step-by-step explanation:Well we know that for two angles A , B

it holds that cos ( A + B ) = cos A cos B − sin A ⋅ sin B hence for A = B you get cos ( 2 A ) = cos 2 A − sin 2 A But sin 2 A = 1 − cos 2 A

7 0

3 years ago

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A student is asked to find a polynomial f(x) of degree four with the zeros 2, -3, 0, and -7. What factors would the student mult

lord [1]

Answer:

(x-2), (x+3),x and (x + 7)

Step-by-step explanation:

Here, the zeros of the polynomial are 2, -3, 0 and -7.

Let’s consider a case of a quadratic equation where x = 5 is a solution. This means that x + 5 is a factor of that quadratic equation.

Now, let’s apply same approach to this polynomial. If x = 2 is a solution, then x -2 is a factor. If x = -3, then, x + 3 is a factor. If x = 0, this means x itself is a solution and lastly, if x = -7 is a solution, that means x + 7 is a factor.

Thus, the factors to multiply together are; (x-2), (x+3),x and (x + 7)

4 0

3 years ago

What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)

Ann [662]

Answer:

The midpoint of points $(-2,-2)\ and\ (4,6)$ is $(1,2)$ .