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3 years ago

Evaluate C=2 pi r for r=8 A. C=10 pi B. C=16 pi C. C=28 pi D. C=16

Mathematics

2 answers:

Verdich [7]3 years ago

5 0

Answer:C

Step-by-step explanation:Because I did this

Brrunno [24]3 years ago

4 0

Answer:

If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`

Step-by-step explanation:

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Inessa [10]

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3 years ago

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Evaluate 3C1. a)3 b)1 c)2 d)6

murzikaleks [220]

Answer: Option a) 3

Step-by-step explanation:

The formula for calculating combinations is as follows

$nCr = \frac{n!}{r!(n-r)!}$

Where "n" is the amount of items in a set and you can choose "r" from them

3C1 reads as: The combination of 1 in 3. You have a set of 3 elements and choose 1 of them.

$n = 3\\\\r = 1$

So :

$3C1=\frac{3!}{1!(3-1)!}\\\\3C1=\frac{3!}{1!*2!}\\\\3C1=\frac{3*2*1}{1*2*1}\\\\3C1=3$

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3 years ago

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Ronch [10]

The formulas for conditional probability are:
$P(A\cap B')=P(A)\cdot P(B'|A)$
$P(A\cap B')=P(B')\cdot P(A|B')$ .
Since $P(A\cap B')= \frac{1}{6}$ and $p(B')= \frac{7}{18}$ , you have the equation $\frac{1}{6} = \frac{7}{18} \cdot P(A|B')$ .
Therefore, $P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}$ .
Answer: The correct choice is D.

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3 years ago

5/7x-4=21 solve folve for x

Aleksandr-060686 [28]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

7*x-4-(21)=0

Solve : 7x-25 = 0

Add 25 to both sides of the equation :

7x = 25

Divide both sides of the equation by 7:

x = 25/7 = 3.571

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3 years ago

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ASHA 777 [7]

4.00 ÷ 0.25 = 16
.70 ÷ 0.05 = 14

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4 years ago