Answer:
The correct answer is - parrot fish - high, Clown fish - high.
Explanation:
According to the first hypothesis, the clown fish developed the immunity to the sea anemone's toxin so there would be a higher number of clown fish that swims among the tentacles of the sea anemones. The parrot fish avoids them also leads to a higher number of these fishes.
The correct graph that supports the first hypothesis that says that the clown fish's developed immunity build by them slowly, a tolerance to the sea anemone's toxin from tentacles of sea anemones.
