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rodikova [14]
3 years ago
9

Find the Sine of angle A 8/17 8/15 15/8 15/17

Mathematics
1 answer:
Vlad [161]3 years ago
7 0

Given:

In triangle ABC, AB = 30, BC = 16, AC = 34 and measure of angle B is 90 degrees.

To find:

The value of Sine of angle A.

Solution:

In a right angle triangle,

\sin\theta=\dfrac{Perpendicular}{Hypotenuse}

In the given triangle ABC,

\sin A=\dfrac{BC}{AC}

\sin A=\dfrac{16}{34}

\sin A=\dfrac{8}{27}

Therefore, the correct option is A.

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Which is the sum of 14t/10t^2 + 5t^2+40t/10t^2
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Answer:

7t/5^3 + 5t^2 + 4t^3

Step-by-step explanation:

4 0
3 years ago
2. Use the following picture for this question:
Art [367]

Answer:

a.  24\sqrt{3}  and 41.6

b.  52.1

Step-by-step explanation:

a.

Considering the left side triangle the blue dotted side is the side "opposite" to the angle given and the side 24 is the side that is "adjacent" to the angle given. The trigonometric ratio tan relates opposite to adjacent. Also, let the blue dotted side be y.

<u>Note:</u> the exact value of tan 60 is \sqrt{3}

Thus, we can write Tan(60)=\frac{y}{24}\\y=24*Tan(60)\\y=24*\sqrt{3} \\y=24\sqrt{3}

Approximate value (rounded to nearest tenth):  24\sqrt{3} =41.6

b.

Considering the triangle to the right, the side "opposite" to the angle given (53 degrees) is 41.6 (just found in part (a)) and the side "hypotenuse" (side opposite to 90 degree angle) is x. The trigonometric ratio sine relates opposite and hypotenuse.

Thus we can write and solve:

Sin(53)=\frac{41.6}{x}\\x=\frac{41.6}{Sin(53)}=52.1

4 0
3 years ago
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horrorfan [7]
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5 0
3 years ago
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nalin [4]
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3 years ago
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