Answer:
b. If there is a linear relationship between the amount of mercury in a lake and the surface area of the lake, the probability of observing a test statistic of 2.086 is 0.05.
( the null is rejected and alternate is accepted)
Step-by-step explanation:
Here the critical value is t≥ t∝/2(n-2) = ± 2.086
The significance level is ∝= 0.05 and the p- value is also 0.05
Which indicates that there is no correlation between the dependent and the independent variable.
If the p - value is less than 0.05 the null hypothesis is rejected.
There is a 5% chance that the hypothesis is true.
So the null hypothesis should be rejected.
Given these options
a) if------as 2.086 or more extreme is 0.05
2.086 or 0.05 is the same in this case one cannot be more extreme.
c) of 2.086 or greater is 0.05.
b). If there is a linear relationship ------.
This is the alternate hypothesis.
0.05 is not greater than 2.086 in the given question
d) If there is not a linear relationship between the amount of mercury in-----.
This is the claim which is formulated as null hypothesis.
e) if---- 2.086 or more extreme is 0.05.
0.05 is the same as 2.086
At p- value 0.05 we reject the null hypothesis and accept the alternate hypothesis
→ 3 ≠ 1 → A is eliminated.
→ 5 ≠
→ B is eliminated.
→ 2 = 2 → C satisfies the equation.
→ 10 ≠
→ D is eliminated.
→ -1 = -1 → E satisfies the equation.
→ 3 = 3 → F satisfies the equation.
