Question

A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?​

Answer 1

Answer:

See below ~

Step-by-step explanation:

Let the father's age be x and son's age be y.

Equations formed :

1. x = y + 25
2. x - 10 = 6(y - 10)

Substitute value of x from Equation 1 in Equation 2.

• y + 25 - 10 = 6(y - 10)
• y + 15 = 6y - 60
• 6y - y = 15 + 60
• 5y = 75
• y = 15

Solution :

1. Son = y = 15 years
2. Father = y + 25 = 15 + 25 = 40 years

Answer 2

Answer:

Present age of son = 15 years

& Present age of father = 40 years

Step-by-step explanation:

• Let the son's present age be x years

• -> Father's present age = (x + 25) years

• 10 years ago:
• Son's age = (x - 10) years

• Father's age = (x +25 -10) = (x +15) years

• It is given that: 10 years ago father was six times as old as his son

• -> x + 15 = 6(x - 10)

• -> x + 15 = 6x - 60

• -> x- 6x = - 60 -15

• -> -5x = - 75

• -> x = -75/(-5)

• -> x = 15

• -> x + 25 = 15 + 25 = 40

• -> Present age of son = 15 years

• & Present age of father = 40 years.