A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?
2 answers:
Answer:
See below ~
Step-by-step explanation:
Let the father's age be x and son's age be y.
Equations formed :
- x = y + 25
- x - 10 = 6(y - 10)
Substitute value of x from Equation 1 in Equation 2.
- y + 25 - 10 = 6(y - 10)
- y + 15 = 6y - 60
- 6y - y = 15 + 60
- 5y = 75
- y = 15
Solution :
- Son = y = 15 years
- Father = y + 25 = 15 + 25 = 40 years
Answer:
Present age of son = 15 years
& Present age of father = 40 years
Step-by-step explanation:
- Let the son's present age be x years
- -> Father's present age = (x + 25) years
- 10 years ago:
- Son's age = (x - 10) years
- Father's age = (x +25 -10) = (x +15) years
- It is given that: 10 years ago father was six times as old as his son
- -> Present age of son = 15 years
- & Present age of father = 40 years.
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