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2 years ago

A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?

Mathematics

2 answers:

vovikov84 [41]2 years ago

4 0

Answer:

See below ~

Step-by-step explanation:

Let the father's age be x and son's age be y.

Equations formed :

x = y + 25
x - 10 = 6(y - 10)

Substitute value of x from Equation 1 in Equation 2.

y + 25 - 10 = 6(y - 10)
y + 15 = 6y - 60
6y - y = 15 + 60
5y = 75
y = 15

Solution :

Son = y = 15 years
Father = y + 25 = 15 + 25 = 40 years

RoseWind [281]2 years ago

3 0

Answer:

Present age of son = 15 years

& Present age of father = 40 years

Step-by-step explanation:

Let the son's present age be x years

-> Father's present age = (x + 25) years

10 years ago:
Son's age = (x - 10) years

Father's age = (x +25 -10) = (x +15) years

It is given that: 10 years ago father was six times as old as his son

-> x + 15 = 6(x - 10)

-> x + 15 = 6x - 60

-> x- 6x = - 60 -15

-> -5x = - 75

-> x = -75/(-5)

-> x = 15

-> x + 25 = 15 + 25 = 40

-> Present age of son = 15 years

& Present age of father = 40 years.

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A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?​

A father is 25 years older than his son. 10 years ago, he was six times as old his son. What are their present ages?