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3 years ago

PLEASE HELP ME THIS IS DUE SOONNN. ILL MAKE IT A LOT OF POINTS AND IF U ANSWER BOTH CORRECTLY ILL GIVE YOU BRAINLIEST PLEASE

Mathematics

1 answer:

alex41 [277]3 years ago

7 0

Answer:

Step-by-step explanation:

3000 600

5000 1000

6000 1200

7500 1500

No it doesn't form a proportional relationship because yes, the ratio is constant AFTER the 5,000, you do need to hit the 5,000 first, and then it changes. So no, it's not proportional because it isn't constant throughout the entirety of the relationship. If you're just going based on the table in question, then yes it will be proportional since it doesn't have the 5,000 in it but if you're looking at it in it's entirety, no it's not.

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Which is equivalent to square root 10st x square root 15tu

aivan3 [116]

$\sqrt{10st}\cdot\sqrt{15tu}=\sqrt{10st\cdot15tu}=\sqrt{150st^{2}u}=\sqrt{25\cdot6\cdot st^{2}u} = \\\\= \sqrt{5^{2} \cdot t^{2}\cdot6 \cdot su}=5t\sqrt{6su}$

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3 years ago

A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

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3 years ago

Which equation represents the volume of a cone with the same base and height as the cylinder below? A cylinder with a height k a

Igoryamba

Answer: The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation: The first important detail to note here is that both cylinder and cone have the same base and the same height This implies that when writing out the formula for calculating the volume of either of the two shapes, the radius and the height will be the same number or value.

The volume of a cylinder is given as;

Volume cylinder = pi x r squared x h (that is πr²h)

Also the volume of a cone is given as;

Volume cone = one-third x pi x r squared x h (that is 1/3*πr²h)

However, the variables have been changed such that the radius r is now represented by t while the height h is now represented by k.

Therefore the volume of the cone should now be re-written as;

Volume cone = one-third pi t squared k <em>(that is 1/3 *πt²k)</em>

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krok68 [10]

Wanda has 2 crayons.

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How do I solve these two?

Bas_tet [7]

Answer:

1.D

2.B

Step-by-step explanation:

For the first one divide see which one is less which is D

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$\frac{15}{1}$ x $\frac{9}{2}$ so multiply the 15 by 9 then you get 135 then divide by 2 so thats your answer

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