Answer:
0.96
Step-by-step explanation:
Answer:
27 and 23
Step-by-step explanation:
We can solve this problem as a system of equations. X is the first number and Y is the second number.
The first equation is x+y = 50 and the second equation is x-y=4
Now we solve the system, using elimination method:
x+y=50
x-y=4
2x = 54
x = 54/2
x = 27
And from any of the equations we can find Y
27 + y = 50
y = 50 - 27
y = 23
This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825
You produced 825 parts in the middle of the shift.
Answer:
Step-by-step explanation:
Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS
