Find the volume of the cone that sits on top of the cylinder

Mathematics

1 answer:

puteri [66]2 years ago

8 0

Answer:

Vc = (π/3)✓17 ≈ 4.12 ft³

Step-by-step explanation:

h = ✓(4²+1²)

h = ✓17

V = πr²h/3

V = π(1)²✓17/3

V = (π/3)✓17 ≈ 4.12

You might be interested in

Given the expression 12 over 12 to the third power.

4vir4ik [10]

Part 1:
Before we begin, you need to remember the following rule:
$\frac{x^a}{x^b} = x^{a-b}$

The given expression is:
$\frac{12}{12^3}$

Since the base is the same in both numerator and denominator, we can apply the above rule. This means that:
$\frac{12}{12^3}$ = 12¹⁻³ = 12⁻²

Part 2:
Before we begin, you need to remember the following rule:
x⁻ᵃ = $\frac{1}{x^a}$

Now, from part 1, we simplified the expression into 12⁻²
Since the power is negative, we can apply the above rule.
This means that:
12⁻² = $\frac{1}{(12)^2} = \frac{1}{12*12} = \frac{1}{144}$

Hope this helps :)

5 0

3 years ago

Read 2 more answers

write a function that has a greater rate of change than one function but a smaller rate of change than the other function

LenaWriter [7]

The function y = 5x has a rate of change that is in between the equation y = 4x and y = 6x.

In an equation, the rate of change is also called the slope. It is the amount that a number is increasing by. We put that value in front of the x in most equations.

In the equal that I gave, the 5 is in between the rates of 4 and 6.

4 0

3 years ago

If ΔABC ≅ ΔDEF, then what corresponding parts are congruent?

labwork [276]

Answer:

its A.

Step-by-step explanation:

5 0

2 years ago

the following histogram shows the number of days during the school year that students bought lunch. How many total students are

olga2289 [7]

You have to post a picture of the actually histogram we can’t see it

5 0

2 years ago

Which of the following estimates at a 95% confidence level most likely comes form a small sample?

KonstantinChe [14]

OptionAStep-by-step explanation:95% confidence interval is obtained using the following formulaCOnfidence interval lower bound = mean - critical value * sigma/sq rt nand upper bound = mean + critical value*sigma/sq rt nThus margin of error = critical value*sigma/rt nvaries indirectly as n provided others are remaining the same.Hence lower sample indicates higher margin of errorOut of 4 options given we find that 1 option has maximum margin of error as 21%Hence option. A is most likely coming from a small sample.

6 0

2 years ago