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Ainat [17]
2 years ago
14

Help meh plzzz buddy UwU

Mathematics
2 answers:
Vinil7 [7]2 years ago
8 0

Answer:

10: The volume is 2cm^{3}

11: The volume is \frac{8}{27}cm^{3}

Step-by-step explanation:

Question 10: (\frac{1}{2} * 4)(\frac{1}{2} * 2)(\frac{1}{2} * 2) = 2 * 1 * 1 = 2cm^{3}

Question 11: (\frac{1}{3} * 4)(\frac{1}{3} * 2)(\frac{1}{3} * 1) = \frac{4}{3} * \frac{2}{3} * \frac{1}{3} = \frac{8}{27}cm^{3}

zhannawk [14.2K]2 years ago
3 0

Answer:

10. 16 cubic cm

11. 5 and 1/3 cubic cm

Step-by-step explanation:

4 · 4 · 2 = 32

32 times 1/2 = 16

2 · 2 · 4 = 16

16 times 1/3

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Three swimmers competed in a 50 m freestyle race. A description of their swimming speeds is given. Order the
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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
netineya [11]

Answer:

see below

Step-by-step explanation:

mROP= 125°

mSOQ= mROP= 125°

mROQ=mPOS= 180°-125°= 55°

<u>Sum of measures of all arcs in the circle= 2π</u>

mRP= mQS=2π*125/360=25/36π

mQR=mPS=2π*55/360=11/36π

mPRQ= half circle= 2π/2= π

mRPQ= 2π-mQR= 2π- 11/36π= 61/36π

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3 years ago
What is the value of x in the following equation? <br> y=3x-5 <br> 6x+3y=15
tatiyna
The value of x is 2. because you rule out y so it is 6times2is 12+3. that is 15

8 0
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How many roots would the quadratic y=x^3+2x^2-12x have?
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Hi! The answer to your questions is 3 Roots

Step-by-step explanation:

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. The manager of a local small bank wants to estimate the average daily balance of all the checking accounts. Assume a random sa
MaRussiya [10]

Answer:

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

Step-by-step explanation:

Consider the provided information.

A random sample of 21 checking accounts at the bank are chosen,

That means n=21

df = n-1

df = 21-1=20

We need to  Construct and interpret a 95% confidence interval.

Determine t critical value for 95% confidence interval.

0.95=1-α

α=0.05

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Substitute the respective values.

CI=303\pm 2.086 \times \frac{63}{\sqrt{21}}

CI=303\pm 28.68

CI=274.32\ or\ 331.68

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

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