9514 1404 393
Answer:
x - 4
Step-by-step explanation:
The expression simplifies to ...
![\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-8x%2B16%7D%3D%5Csqrt%7B%28x-4%29%5E2%7D%3D%7Cx-4%7C)
For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...
x - 4 . . . . for x ≥ 4
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
2.4cm is the tangent of A
Answer:
no solution
Step-by-step explanation:
3<7x−5<−3