Two angles are alternate to each other. One of the

Find the cube of 2/3

Murrr4er [49]

Answer:

8/27

Step-by-step explanation:

$\huge \bigg( \frac{2}{3} \bigg)^{3 } = \frac{ {2}^{3} }{ {3}^{3} } = \frac{8}{27} \\$

5 0

3 years ago

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How do you find the zeros of an equation

lubasha [3.4K]

Answer:

Step-by-step explanation:

In general, given the function, f(x), its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.

5 0

2 years ago

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PLEASE ANSWER AND EXPLAIN | 98 POINTS

9966 [12]

Answer:

d

0.9

The value of a correlation coefficient ranges between -1 and 1.

The greater the absolute value of the Pearson product-moment correlation coefficient, the stronger the linearrelationship.

The strongest linear relationship is indicated by a correlation coefficient of -1 or 1.

The weakest linear relationship is indicated by a correlation coefficient equal to 0.

A positive correlation means that if one variable gets bigger, the other variable tends to get bigger.

A negative correlation means that if one variable gets bigger, the other variable tends to get smaller.

hope it helps.

3 0

3 years ago

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A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Are the length of a side of a square and the area of the square related proportionally? Why or why not?

Sliva [168]

Answer:

Yes, the length of a side of a square and the perimeter of the square are related proportionally.

Step-by-step explanation:

4 0

2 years ago