Answer:
B. The functions f(x) and g(x) are reflections over the y-axis.
Step-by-step explanation:
From the information given the table appears as;
x f(x)=2^x g(x)=0.5^x
2 4 0.25
1 2 0.5
0 1 1
-1 0.5 2
-2 0.25 4
Plotting the two graphs to view the trends;
In the graph of f(x)=2^x against x you notice a curve with increasing positive slope.
In the graph of g(x)=0.5^x against x you notice a curve with a negative slope that is increasing.
In combining both graphs you notice that f(x) and g(x) are reflections over the y-axis.
Correct answer is ;The functions f(x) and g(x) are reflections over the y-axis.
we have to find equation similar to
Firstly , we can divide both sides by 2
now, we can multiply both sides by 3
we get
............Answer
Answer:
16
Step-by-step explanation:
To get the next number just mulitply by 4
4*4=16
( just to make sure we're correct)
16*4=64
64*4=256
256*4=1024
1024*4=4096
The domain of 13/x - 11 is all real numbers except x cannot equal zero
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
