Because
therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k = constant.
Because f(3) = 4, therefore k =4.
The polynomial is
f(x) = 2x³ + 10x² - x - 6x² - 30x + 3 + 4
= 2x³ + 4x² - 31x + 7
Answer: f(x) = 2x³ + 4x² - 31x + 7
Answer:
C) The angles in a square measure 90 degrees. The rhombus has obtuse and
acute angles.
Step-by-step explanation:
Answer:
No solution
Step-by-step explanation:
There is not a real nor an imaginary solution to this equation. You can use a radical calculator to verify.
X=7 What you can do is look at the first two values given, and make them x1 and y1. Then your next value here is y2.
So x1 is 14, and y1 is 3. y2 becomes 6. X2 is unknown.
Then make the formula: x1/y2 is equal to x2/y1
(You are setting two fractions equal to each other)
That makes 14/6=X/3. When we cross multiply, we find that x=7.
The equation you wrote has no solutions since the left hand side is equal to 6x-10 and the right hand side is equal to 6x+8. Setting them equal we get -10=8 which is obviously wrong.
