Originally, both range() and xrange() produced numbers that could be iterated over with ... whereas reversed() is generally used to loop over a sequence in reverse order. ... Once you have it installed, put in the following:.
Answer:
14
Step-by-step explanation:
You add 50 and 26 together to get 76, then you subtract 90 and 76 to get 14
Since the line is parallel, the same coefficients can be used for x and y. The constant on the right needs to change so that the given point will satisfy the equation.
... 5x - 4y = 5(-8) -4(2) = -40 -8 = -48
Your equation is
... 5x -4y = -48
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
Answer:
The equation of the new line is 
or 
Step-by-step explanation:
step 1
Find out the slope of the line with x-intercept (3,0) and y intercept (0,3)
The formula to calculate the slope between two points is equal to
substitute the values
step 2
Find the slope of the new line perpendicular to the given line
we know that
If two lines are perpendicular,then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
we have
----> slope of the given line
so
---> slope of the new line
step 3
Find the equation of the new line in point slope form
we have
substitute
----> equation in point slope form
Convert to slope intercept form
isolate the variable y
