Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
1000000
Hope this helps! :)
So earned 56,700 in a year and had 8,788.5 held back
convert to percent
so find what percent was withhelald which is (amount held back)/(total taken from)
so it would be 8,788.5/56,700=0.155/1
percent means parts out of 100 or x/100=x% so convert the bottom number ot 100 by mulitplyint the whole fraction by 1 or 100/100 so
0.155/1 times 100/100=15.5/100=15.5%
the answer is 15.5%
Answer:
See explanations for step by step procedure to answer
Step-by-step explanation:
Given that;
.f (x comma y )equals 8 x squared y minus 3 Confirm that the function f meets the conditions of the Second Derivative Test by finding f Subscript x Baseline (0 comma 0 ), f Subscript y Baseline (0 comma 0 ), and the second partial derivatives of f.
See attached documents for clearity, further explanations and answer
