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3 years ago

Is 4 to 7 the same as 7 to 4? Explain why or why not.

Mathematics

2 answers:

gladu [14]3 years ago

5 0

Answer:

Step-by-step explanation:

4 to the 7th power would be 4X4X4X4X4X4X4 which equals 16384

while 7 to the 4th power would be 7X7X7X7 which equals 2401

hope this helps

Galina-37 [17]3 years ago

3 0

Answer: no

Step-by-step explanation:

4 is smaller than 7. And 7 is greater than 4 so let's just say ur solving a division problem multiplication ect you always need to put the greater number first!

So yeah hope I helped! <3

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sarita used 54 oz. of apples to make an apple pie. how many pounds and ounces of apples did sarita use?

sergejj [24]

The highest we can go is 48 oz
3 lbs is 48 oz
54-48= 6
So the answer is
Answer: 3 lbs and 6 oz

Hope i helped <3

5 0

3 years ago

Find the slopes of line j and line k. Are they parallel? IF U ANSWER RIGHT I WILL MARK BRAINLIEST PLEASE ANSWER NEED ANSWER FAST

zloy xaker [14]

Answer:

The lines are certainly not parallel!

Step-by-step explanation:

The slope of line J is 3/2, while the slope of line k is exactly 1 :)

5 0

3 years ago

Read 2 more answers

The length of a rectangle is twice the width. the perimeter is 32 cm more than the width. find the dimensions of the rectangle.

SCORPION-xisa [38]

Width: x
Length: 2x
Perimeter=2x+2x+x+x=6x
32 cm more than width means x+32
6x=x+32
5x=32
x=6.4
Dimension is 6.4×12.8 (width×length)

7 0

3 years ago

Multiply. Enter your answer as a simplified mixed number. -4(3/14)

Rus_ich [418]

Answer:

-53 /14

Step-by-step explanation:

6 0

2 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago