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EastWind [94]
3 years ago
7

Write the differential equation model that fits the given description. (a) The rate of change of the volume of a snowball (due t

o melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3 . (b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.
Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

\frac{dV(t)}{dT} = A*V(t)^{2} \\ and V(0) = 900cm^{3}

where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to V(t)^{2}. Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

\frac{dr(t)}{dt}  = B*\sqrt{r(t)}

Here again appears a constant B for the "proportional" part. And i wrote the velocity as \frac{dr(t)}{dt} "the rate of change of the position with respect to te time".

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There were 57 cars in a parking lot at 9:00 AM and 36 different cars at 8:00 PM.
Dmitry [639]

Answer:

C. 93 cars

Step-by-step explanation:

57 cars + 36 cars = 93 cars

7 0
2 years ago
(PLEASE!!!!) The congruency of MNO and XYZ can be proven using a reflection across the line bisecting OZ. However, this congruen
finlep [7]

Explanation:

Only the reasons need be given here, as the statements are already given in your figure.

  1. Given
  2. Given
  3. Given
  4. Definition of congruent line segments
  5. Symmetric property of congruence
  6. Addition and substitution properties of equality*
  7. Segment addition theorem
  8. Definition of congruent line segments
  9. AAS congruence postulate

_____

* The addition property says if A=B, then A+C=B+C. The substitution property further says if C=D, then A+C=B+D (D can be substituted for C). IMO, both properties are needed together to get from A=B and C=D to A+B=C+D.

6 0
3 years ago
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Theo and Kade worked on a school project together. Theo worked on the project 3 fewer hours than Kade did. Altogether, they work
kari74 [83]

Answer:

Theo worked on it for 12 hours. Kade worked on it for 15 hours.

Step-by-step explanation: 12 plus 15 equals 27.

3 0
2 years ago
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A rope is tied to the bottom of a hot air balloon ad shown below The rope makes an angle of 35 with the ground and is 75 ft long
damaskus [11]

Answer:

The answer to your question is 43 ft

Step-by-step explanation:

Data

angle = Ф = 35°

length = 75 ft

height = ?

Process

To solve this problem, use trigonometric functions. The trigonometric function that relates the Opposite side (height) and the hypotenuse (length) is sine.

               sin Ф = Height / length

-Solve for height

                height = length x sin Ф

-Substitution

                height = 75 x sin 35

-Simplification

                height = 75 x 0.574

-Result

                 height = 43 ft

6 0
3 years ago
In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

8 0
3 years ago
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