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2 years ago

Which of the following statements is true for ∠a and ∠b in the diagram?

Mathematics

2 answers:

Iteru [2.4K]2 years ago

8 0

Answer:

B because they are the same angle

Dafna1 [17]2 years ago

6 0

Answer:

B. m∠a = m∠b

Step-by-step explanation:

This statement is true due to the Alternate Interior Angle Theorem, which states: If ∠a = x, then ∠b = x, meaning that if a equals a certain angle measure, then the alternate interior angle, or the angle opposite a, must also be the same measure.

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In a certain year the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell

zavuch27 [327]

Answer:

Fell by 25%

Step-by-step explanation:

+20% January

-20% February (20-20 is zero, so we're back to the original price we started at here)

+25% March

?? April

Currently, we are 25% more than what we had, so to get back to normal, the price needs to go down by 25 percent. This will put us back to zero. Put another way...

+20%-20%+25%-25%=0% (Original Price)

8 0

2 years ago

Please help ASAP on question b

max2010maxim [7]

Answer:

13.9cm

Step-by-step explanation:

13^2 = 169

5^2 = 25

169 + 25

= 194

13.9

8 0

2 years ago

Read 2 more answers

When 8 is added to a certain number and the

Mars2501 [29]

Answer:

Step-by-step explanation:

11+8=19

19x3=57

7 0

2 years ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

2 years ago

Which solid figure does this net represent? A) Eliminate B) square pyramid C) triangular prism D) triangular pyramid

vampirchik [111]

It represent a square pyramid

6 0

3 years ago