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3 years ago

What is the absolute value of the complex number -4 - square root of -2i

Mathematics

1 answer:

hichkok12 [17]3 years ago

8 0

Absolute value of a complex number is sqrt(a^2 + b^2) sqrt(16+4) = sqrt(20)= 2sqrt5

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<img src="https://tex.z-dn.net/?f=%28%5Csqrt%7B20%7D%20-%202%5Csqrt%7B45%7D%20%2B%5Csqrt%7B5%7D%20%29%2A%5Csqrt%7B5%7D" id="TexF

nataly862011 [7]

Answer:

Step-by-step explanation:

$(\sqrt{20} - 2\sqrt{45} +\sqrt{5} )*\sqrt{5}$

$= \sqrt{20} \times \sqrt{5} - 2 \sqrt{45} \times \sqrt{5} + \sqrt{5} \times \sqrt{5}$

$= \sqrt{100} - 2 \sqrt{225} + \sqrt{25}$

= 10 - 2 × 15 + 5

= 10 - 30 + 5

= 15 - 30

= -15 (Ans)

7 0

3 years ago

In Euclidean geometry, the sum of the lengths of 2 sides of a triangle is greater than the length of the third side. The lengths

bearhunter [10]

Answer: $x \in (\frac{5}{3},\frac{19}{3})$

Step-by-step explanation:

Given

length of three sides are

$3x, 7\ and\ 12$

according to Euclidean geometry

$7+12>3x$

$19>3x$

$\frac{19}{3}>x$

also

$3x+7>12$

$3x>5$

$x>\frac{5}{3}$

therefore value of $x \in (\frac{5}{3},\frac{19}{3})$

If x is an integer then x can be $2,3,4,5,6$

7 0

4 years ago

The vertex of the graph of y = -4(x + 3)2 + 2 is ( , )

andrezito [222]

Answer:

Step-by-step explanation:

This quadratic is of the form

$y=-a(x-h)^2+k$ where h and k are the coordinates of the vertex. Notice that inside the parenthesis it very specifically follows the format (x - h)². That means that if you have something like what we have here, ( x + 3)^2, it was originally (x - (-3))^2, and the value for h is -3. k is much simpler to determine. Our 2 at the end is a +2, so the k is 2. The vertex then is (-3, 2).