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3 years ago

Which is the cosine ratio of ∠A?

Mathematics

1 answer:

omeli [17]3 years ago

4 0

Answer:

d . 19528

Step-by-step explanation:

maaf jika salah

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Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?

lilavasa [31]

We have the following function:
f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
We note that the function depends on x because it is f (x).
However, there is no variable x in the function.
Therefore we can assume that the function is constant, since:
a = constant
b = constant
Therefore, the degree of the function is zero
Answer:
The function is zero degree.

7 0

3 years ago

Evaluate 12 x (4^-2/4^-4) A 1/4 B 3/4 C 16 D 192

MrMuchimi

12 ×4^4/4^2
=12×4^2
=12×16
=192

7 0

3 years ago

3 moon + 1 star = 29 1 moon +1 moon = 15 Find value of 1 moon

Montano1993 [528]

Hi!

I can help you with joy!

3 moons+1 star equals 29.

All right.

Actually, there are a few numbers that can be hidden behind the moon:

3*8=24 + 1 star (5) = 29

But 1 moon + 1 moon equals 15.

So one moon equals 7.5.

$*GentleGirlie*$

8 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

In the 1980s an average mortgage rate was around 18.5 how much less per month would a 150000 30 year mortgage by today if the cu

lianna [129]

Answer:

$1516.69 per month less

Step-by-step explanation:

The formula for the monthly payment A on a loan of principal P, annual rate r, for t years is ...

A = P(r/12)/(1 -(1 +r/12)^(-12t))

For the 18.5% loan, the monthly payment is ...

A = 150000(.185/12)/(1 -(1 +.185/12)^(-12·30)) ≈ 2321.92

For the 5% loan, the monthly payment is ...

A = 150000(.05/12)/(1 -(1 +.05/12)^-360) ≈ 805.23

The mortgage at 5% would be $1516.69 less per month.

7 0

3 years ago