Answer: Train A = 50 mph; Train B = 30 mph
Step-by-step explanation:
In this case, let's call the speed of both trains as:
Va: speed of train A
Vb: speed of train B
As train A is faster than train B, let's call speed of train B as X; So if Vb is X, then Va would be:
Vb = X
Va = X + 20
If we combine both Speed, we have:
V = Va + Vb = X + X + 20 = 2X + 20
Now that we have an expression for the combined speed, let's recall the formula for speed in general:
V = d/t
Where:
d: distance = 240 miles
t: time = 3 hours
Combining all the data we have:
V = 240/3
but V is 2X + 20 so:
2X + 20 = 240/3
Solving for X:
2X + 20 = 80
2X = 80 - 20
2X = 60
X = 60/2
X = Vb = 30 mph
Now that we know speed of one train, we can know the speed of the other train:
Va = 30 + 20 = 50 mph
Answer:
modify tge production
Step-by-step explanation:
Answer:
positive, its above 0
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
18 and 35. The numbers whose sum 53 are 18 and 35.
The key to solve this problem is using a system of equations.
There are two numbers whose sum is 53. This number can be represented as x and y. So:
x + y = 53
Three times the smaller number is equal to 19 more than the larger. Let's set x as the smaller number and y the larger number. So:
3x = 19 + y
Clear y in both equations and let's use the equalization method to solve for x:
y = 53 - x and y = 3x - 19
Then,
53 - x = 3x - 19
53 + 19 = 3x + x ---------> 3x + x = 53 + 19 -------> 4x = 72
x = 72/4 = 18
To find y, let's substitute x = 18 in the equation x + y = 53
18 + y = 53 --------> y = 53 - 18
y = 35
