Given:
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
To find:
The probability of both events occurring, in that order.
Solution:
If A and B are two independent events, then
It is given that,
The probability for success of an event is P(A)
The probability of success of a second, independent event is P(B).
Since A and B both are independent event and we need to find the probability of both events occurring, in that order, i.e., 
, therefore .
Hence, the correct option is A.
Okaayyy
Set B has the greater mode
Answer:
x = -5
y = 2
Step-by-step explanation:
x = – 2y – 1
= -x - 2y - 1
-x - 2y = 1
x = – 5y + 5
= -x - 5y + 5
-x - 5y = -5
-x - 2y = 1
-x - 5y = -5
___________--
3y = 6
y = 6/3
<u>y = 2</u>
-x - 2y = 1
-x - 2(2) = 1
-x - 4 = 1
-x = 1 + 4
-x = 5
<u>x = -5</u>
Answer:
let the number of cows = x
let the number of chickens = y
since there are 42 heads:
x + y = 42
and since a cow has 4 legs, and a chicken has 2
4x + 2y = 144
from first equation:
x + y = 42
x = 42 - y (now, we will substitute this in the second equation)
4(42 - y) + 2y = 144
168 - 4y + 2y = 144
2y = 168 - 144
2y = 24
y = 12
now, we know the number of chickens. we will replace y with 12 in the first equation since it is more simpler
x + 12 = 42
x = 30
So, there are 30 cows and 12 chickens
Brainly it if you find the answer helpful
