Answer:
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Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
Angle 3 and 5 are alternate interior angles, please mark me Brainliest!
Factor out the trinomial. Find factors of x² and 6 that would, when added, give you 5x
x² = x * x
6 = 3 * 2
(x + 3)(x + 2) are your binomials.
To solve for x, set each parenthesis = 0
x + 3 = 0
x + 3 (-3) = 0 (-3)
x = -3
x + 2 = 0
x + 2 (-2) = 0 (-2)
x = -2
x = -3, -2
hope this helps
Answer:
7x
Step-by-step explanation:
