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3 years ago

5

Which of the following situations best represents a random sample?

1 answer:

PilotLPTM [1.2K]3 years ago

3 0

Answer:

B

PLZZZZZZZ GIVE ME BRAINLIEST

Step-by-step explanation:

You might be interested in

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

3 years ago

For every 3 apples in a

Irina18 [472]

Answer:

18 apples equals 6 bananas

6 0

2 years ago

Read 2 more answers

Which is a solution -2x-y=1 and -4x-2y=-1

grin007 [14]

Answer:

No solutions.

Step-by-step explanation:

-2x - y = 1

-4x - 2y = -1 Multiply the first equation By -2:

4x + 2y = -2 Adding:

0 = -3

which is absurd so there are no solutions.

7 0

3 years ago

a circle is inscribed in a square. the circumference of the circle is increading at a constant rate of 6 inches per second. As t

Burka [1]

Answer:

The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

Step-by-step explanation:

Given:

Circumference of the circle = $2\pi r$

Rate of change of in circumference = 6 in/secs

We need to find the rate at which the perimeter of the square is increasing

Solution:

Now we know that;

$\frac{d(2\pi r)}{dt} =6\\\\2\pi\frac{dr}{dt}=6\\\\\frac{dr}{dt}=\frac{6}{2\pi}\\\\\frac{dr}{dt}=\frac{3}{\pi}$

Now we know that;

side of the square= diameter of the circle

side of the square = $2r$

Now Perimeter of the square is given by 4 times length of the side.

$P=4\times 2r =8r$

Now we need to find the rate at which Perimeter is increasing so we will find the derivative of perimeter.

$\frac{dP}{dt}= \frac{d(8r)}{dt}\\\\\frac{dP}{dt}= 8\times\frac{dr}{dt}$

But $\frac{dr}{dt} =\frac{3}{\pi}$

So we get;

$\frac{dP}{dt}= 8\times\frac{3}{\pi}\\\\\frac{dP}{dt}= \frac{24}{\pi}\ in/sec$

Hence The rate at which Perimeter of the square is increasing is $\frac{24}{\pi} \ in/secs$ .

5 0

3 years ago

If 8 x = 24, then x = ?

Tju [1.3M]

8x = 24...divide both sides by 8
x = 24/8
x = 3 <==

3 0

3 years ago

Read 2 more answers