Answer:
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
6x^10 − 96x^2
Factor out 6x^2
6x^2 ( x^8 - 16)
Notice that inside the parentheses we have the difference of squares
6x^2 ( x^4 ^2 - 4^2) a^2 - b^2 = (a-b) (a+b)
6x^2 ( x^4 -4) (x^4 +4)
Notice that x^4-4 is also the difference of squares
6x^2 ( x^2^2 -2^2) (x^4 +4)
6x^2 ( x^2 -2) ( x^2 +2) (x^4 +4)
Note also that x^4 + 4 can be factored into (x^2+2x+2)(x^2-2x+2)
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Answer:
infinite
Step-by-step explanation:
Let the linear equation in two variables be ax+by+c=0
Put values
Hence for any values it has infinite number of solutions .
including x=1 and y=3
12 is first one 7 is 2nd one 9 is the last one
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
1. 15 (A)
2. 12 (G)
Step-by-step explanation:
1. We can make an equation out of this...
3x+3=48
x is the age of Geoff which is what we are trying to find out
We have to add 3 to both sides of the equation
3x+3=48
-3 -3
________
we end up with 3x=45
we then have to divide 3 by both sides because its the opposite of
multipling
3x=45
_____
3
we get x=15
2. We can write a problem statement
(2 x 9)-6=?
multiply 2 and 9 <u>FIRST</u>
18-6=?
your answer is 12
Your Welcome! Have a great rest of your day! :)
