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How many linear equations in x and y can have a solution as (x = 1, y = 3)?

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Mathematics

2 answers:

Shkiper50 [21]2 years ago

6 0

Answer:

infinite

Step-by-step explanation:

Let the linear equation in two variables be ax+by+c=0

Put values

$\\ \sf\longmapsto 1a+3b+c=0$

$\\ \sf\longmapsto a+3b+c$

Hence for any values it has infinite number of solutions .

including x=1 and y=3

Ilia_Sergeevich [38]2 years ago

4 0

Answer:

<h3>infinitely many equations</h3>

A linear equation in two variable is of the form ax+by+c=0.

We have x=2 and y=3 but we can choose a,b,c accordingly and they can attain infinite values. So, Infinite such equations exist.

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Answer:

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Step-by-step explanation:

x and x+2

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x+3x+6=98

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Answer:

Stephen's wife got £354 more than his son.

Step-by-step explanation:

Given:

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Now Given:

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Now Given:

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Dividing both side by 10 we get;

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And Stephen's son share = $2y=2\times118 =\£236$

Now we need to find how much more her wife got then her son.

To find how much more her wife got than her son we will subtract Stephen's son share from Stephen's wife share.

framing in equation form we get;

Amount more her wife got than her son = $590-236 = \£354$

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Step-by-step explanation:

<u>Graph of the function:</u>

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<em>The graph is attached</em>

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Answer:

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