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2 years ago

1. Is the following a Function? (2,3) (4,7) (3,9) (5,7)

Mathematics

2 answers:

tia_tia [17]2 years ago

5 0

Answer: like wheres the graph

do u have a graph

Step-by-step explanation:

QveST [7]2 years ago

4 0

Answer:

Yes.

Step-by-step explanation:

Every x (first numbers in pairs) is different, so the relation is a function. There are two of the same y's (second numbers in pairs), but that's okay to have in a function.

Hope this helps you!! Have a nice day ^^

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I need help with some tutorverse questions, thanks!

Aloiza [94]

Answer:

11. c

12. c

Step-by-step explanation:

11. Since Angle RST = 60 degrees, Angle RTS = 60 degrees.

Triangle STU is a right triangle, so Angle STU and Angle SUT are both 45 degrees.

Angle RTS + Angle STU + Angle UTQ = 180 degrees

60 + 45 + Angle UTQ = 180

Angle UTQ = 180 - 105

= 75 degrees

12. Using the corresponding angles theorem, x = 45 degrees and y = 35 degrees.

x + y

45 + 35

8 0

1 year ago

Read 2 more answers

What's the explicit rule for the sequence 3, -6, 12, -24, 48, ...?

777dan777 [17]

Answer:

$\sf \dfrac{-3}{2}(-2)^n$

Step-by-step explanation:

Explicit formulas are used to represent all the terms of the geometric sequence with a single formula.

$\sf \boxed{\bf t_n = ar^{n-1}}$

a is the first term.

r is the common ratio.

r = second term ÷ first term.

3 , - 6 , 12, - 24, 48 ,........

a = 3

r = -6 ÷ 3 = -2

$\sf t_n = 3*(-2)^{(n-1)}\\\\$

$\sf = 3*(-2)^{n}*(-2)^{-1}\\\\ =3*(-2)^n*\dfrac{-1}{2}\\\\= \dfrac{-3}{2}(-2)^n$

Check:

$\sf t_1 =\dfrac{-3}{2}*(-2)^1=\dfrac{-3}{2}*(-2) = 3\\\\\\t-2 = \dfrac{-3}{2}*(-2)^2 = \dfrac{-3}{2}*4=-6\\\\\\t_3=\dfrac{-3}{2}*(-2)^3=\dfrac{-3}{2}*(-8)=12$