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VLD [36.1K]
3 years ago
5

Help me with this please everyone

Mathematics
2 answers:
LenKa [72]3 years ago
3 0
A. $1.50
B. $ 4.50
C. $2
Ronch [10]3 years ago
3 0
(a)$9=3 peanuts
1 peanut=$9/3
              =$3
(B)$9=2 peanuts+2 pretzels
         =(2*3)+2pretzels
         =$6+2pretzels
2pretzels=$9-$6
              =$3
1pretzel=$3/2
             =$1.50
(c)$9=1peanut+1pretzel+1milkshake
        =$3+$1.50+1milkshake
        =$4.50+1milkshake
1milkshake=$9-$4.50
                  =$4.50
$4.50/$1.50=3
3 pretzels can be bought with the amount of money to buy 1 milkshake

Hope u understand

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A local salesman receives a base salary of $975 monthly. He also receives a commission of 6% on all sales over $1200. How much w
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He has to sell in a month $26616.67.

Given that a local salesman receives a base salary of $975 monthly and he also receives a commission of 6% on all sales over $1200.

A numerical assertion wherein two articulations are delivered equivalent to each other is known as an algebraic condition.

Let the Sales amount be s.

We have:

Sales over 1,200 is written as

s-1200

6% is also 0.06  as a decimal,

so according to question, we have

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Now, we will apply the distributive property a(b+c)=ab+ac, we get

0.06s-0.06×1200+975=2500

Further, we want to simplify the left-hand side, we get

0.06s-72+975=2500

0.06s+903=2500

Furthermore, we will subtract 903 from both sides, we get

0.06s+903-903=2500-903

0.06s=1597

Now, we will divide both sides with 0.06, we get

0.06s/0.06=1597/0.06

s=26616.67

Hence, he have to sell in a month if he needed to have a monthly income of $2500 is $26616.67.

Learn more about algebraic equation from here brainly.com/question/4344214

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Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed
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Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

n=9\times17576=175760.

Thus, the required number of passwords that can be created is 175760.

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