I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
<span>Assuming that Josh throws the discus 36 times, the expected value of y will be the length each discus reaches for each throw all added together. Specifically, it will be discus throw one, plus discus throw two -- all the way to discus throw thirty-six. Adding all of those throws together will provide the expected value of Y.</span>
Answer:
Y=x^2-2x-8,x , x=r
Binomial with degree of 3
