Given:
To find:
The exponential form of given equation.
Solution:
We have,
According to the property of the logarithm,
Using the above property of the logarithm, we get
Therefore, the required equation in exponential form is .
1.a.
3 1/3 - 2 5/6 =
= 10/3 - 17/6
= 20/6 - 17/6
= 3/6 = 1/2
1.b.
1/2 * 3 1/3 + 1/2 * 2 5/6 =
= 1/2 * 10/3 + 1/2 *17/6
= 10/6 + 17/12
= 20/12 + 17/12
= 37/12
= 3 1/12
2.a.
2 1/3 - 1 1/2 =
= 7/3 - 3/2
= 14/6 - 9/6
= 5/6
2.b.
1/12 * 5/6 = 5/72
3.
3 3/8 * 3 =
= 27/8 * 3/1
= 81/8
= 10 1/8
4.
6 1/4 - 5 1/2 =
= 25/4 - 11/2
= 25/4 - 22/4
= 3/4
(3/4)/(6 1/4) =
= (3/4)/(25/4)
= 3/4 * 4/25
= 3/25
Answer:
2x-z=0 is the equation of the plane.
Step-by-step explanation:
Given that the plane passes through the points (1,0,2) and (-1,1,-2)
and also origin.
Hence equation of the plane passing through three points we can use
Any plane passing through 3 given points is given as
Substitute the three points to get
2x-z=0 is the equation of the plane.
B = no. of buses
v = no. of vans
b + v less than or equal to 8 ( there are only 8 drivers, but don't have to use them all)
51b + 8v greater than or equal to 193 (the number of seats must be at least 193 but there can be spares)
So these are the inequalities to solve. I did start doing a linear programming graph but the second inequality is horrible so I hope you don't need to actually solve them.