a truck can travel 160 miles in the same time that it takes a car to travel 200 miles. If the truck's rate is 10 miles per hour slower than the car's find the average rate for each.
the rate of the car is miles per hour
Answer:
are=πr²
3.14*8*8
=200.96 inches²
Step-by-step explanation:
Answer:
It is 2/7 please mark me brainliest
Step-by-step explanation:
Answer:
14%
Step-by-step explanation:
To get the percent increase divide 0.8 by 0.7
0.8/0.7 ≈ 1.14285714286
So the percent increase would by about 14 percent
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
