Answer:
Is there a picture
Step-by-step explanation:



Answer:
30/182 = 15/91.
Step-by-step explanation:
<u>PROBABILITY:</u> the likelihood of an event.
There are a total of 14 shirts in the basket.
Of the 14, 8 (8/14) of them are white, and 6 (6/14) of them are black.
The probability of picking a black shirt is 6 in 14, or 6/14.
The probability of picking a white shirt is 8 in 14, or 8/14.
<u>WITHOUT REPLACING:</u> This means that you take one without putting it back. (There will be one less).
6/14 × 5/13 = 30/182.
30/182 = 15/91.
Answer:
The correct option is B. 23%
Step-by-step explanation:
Let the event that patient brushes his teeth at least twice a day is denoted by A
So, P(A) = 0.83
Let the event that patient flosses daily is denoted by B
So, P(B) = 0.47
Now, it is given that 19 percent patients brush at least twice a day and floss daily.
⇒ P(A and B) = 0.19
Now, we need to find conditional probability of occurring event B given A has occurred.

Hence, Nearest required percentage = 23%
Therefore, The correct option is B. 23%
Simplify (2+5-10) and then it's -3 and then (7x)(-3) = -21