Answer:
55°
Step-by-step explanation:
Draw the diagram according to the given data (see attached diagram).
In this diagram,
- line AC is runway A;
- line BD is runway B;
- line AB is runway C.
Note that ∠GCH=35°
Angles GCH and CDI are corresponding angles. By corresponding angles postulate, angles GCH and CDI are congruent.
Angles CDI and BDE are vertical angles, so angles CDI and BDE are congruent as vertical angles.
Consider right triangle BDE. The sum of two acute angles of the right triangle is 90°, so
m∠BED=90°-m∠BDE
m∠BED=90°-35°=55°
The Correct answer is 1,372
Recall that a circle of radius 2 centered at the origin has equation
where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius
is
, it follows that the area of a quarter-circle would be
.
You have
, so the definite integral is equal to
.
Another way to verify this is to actually compute the integral. Let
, so that
. Now
Recall the half-angle identity for cosine:
This means the integral is equivalent to
U should Divide the ones first then the tenths
Answer:
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