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I hope this answers is helpful
Answer:
3. 1. 2. daily, weekly, monthly
Explanation:
Answer:
b.used is 2, b.data[0] is 4, b.data[1] is 6
Explanation:
bag b;
b.insert(5); // b has 5
b.insert(4); // b has 5,4
b.insert(6); // b has 5,4,6
b.erase_one(5); // now 5 is removed , b has 4,6
so no:of elements b.used is 2
b[0]=4;
b[1]=6;
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Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver
